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Pipeline parallelism

Compare kernel, parallelism and disaggregated-serving choices using memory, communication and latency constraints.

Pipeline parallelism

Pipeline parallelism assigns consecutive layers to different devices (stages). Activations flow from stage to stage and several microbatches are in flight at once. Ideal speed-up is limited by two things: the bubble of idle time while the pipeline fills and drains, (p − 1)/(m + p − 1) of the schedule for p stages and m microbatches, and imbalance, because the slowest stage sets the pace for all.

stage 1 ms10stage 2 ms10stage 3 ms20stage 4 ms10microbatches8
slowest stage: stage 3 (20 ms) → steady rate 50 microbatches/s re-balanced (12.5 ms each) → 80 microbatches/s total time for 8 microbatches: 190 ms; idle fraction at equal stages (p−1)/(m+p−1) = 0.273

Each stage holds a slice of the layers and passes activations to the next. At the start and end some stages are idle (the bubble), and one slow stage sets the pace of the whole pipeline.

Make one stage slower and watch the rate fall; compare with a balanced split.

Predict first. Does one slow stage affect the overall pipeline rate?

Chapter context

Scaling serving changes how work is placed and moved. An operation can be mathematically unchanged while its memory traffic changes dramatically. Device count alone does not describe the performance of the resulting system.

Chapter reference: math, worked example & code

This section belongs to the whole chapter, so it is the same on every lesson in it and may cover a different lesson's topic. The code for the experiment you just ran is inside the experiment itself.

Math and notation

A weight-traffic lower-bound estimate is

tstep≳Mread/BW.t_{step}\gtrsim M_{read}/BW.

This assumes the stated bytes really traverse the bottleneck bandwidth. KV transfer adds roughly bytes_to_move/network_bandwidth before protocol and synchronization overhead. Batching and caching can change the bytes per produced token.

Worked example

A fictional 14-GB dense weight scan across a sustained 700-GB/s memory path takes at least 14/700=0.02 seconds, giving a 50-step/s bandwidth ceiling under the one-scan-per-step assumption. Real execution includes other memory traffic and work. A 512-MiB KV transfer over 32 GiB/s has a payload-only lower bound of 1/64 second.

Reference code

The following example uses the Python standard library and does not call a remote service.

from math import isclose
assert isclose(14/700,.02)
assert isclose(1/(14/700),50)
transfer=(512*1024**2)/(32*1024**3)
assert isclose(transfer,1/64)

Python examples are provided for study and local execution; this page does not execute Python.

Common mistakes

Peak device bandwidth is not guaranteed sustained application bandwidth. Exact attention can be computed with different memory layouts. Additional GPUs can add communication bottlenecks.