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Tensor parallelism

Compare kernel, parallelism and disaggregated-serving choices using memory, communication and latency constraints.

Tensor parallelism

When a model does not fit on one device, tensor parallelism splits individual weight matrices across devices. Split a matrix by columns and each device produces its own slice of the output, which is concatenated. Split by rows and each device produces a partial sum of the full output, which must be added with an all-reduce. Either way devices must exchange data: splitting the weights saves memory per device but adds communication to every layer.

devices p4
device 1
device 2
device 3
device 4
column split: each device computes its own columns of the output → results are CONCATENATED (a gather)
weights per device: 14 GB / 4 = 3.5 GB ring all-reduce of 16,384 bytes over 4 devices: 24,576 bytes sent per device

A transformer MLP splits the first matrix by columns and the second by rows, so a single all-reduce is needed at the end. Splitting the weights saves memory per device but never removes the communication.

Choose the split direction and the number of devices.

Predict first. Is splitting weights enough to avoid all cross-device exchange?

Chapter context

Scaling serving changes how work is placed and moved. An operation can be mathematically unchanged while its memory traffic changes dramatically. Device count alone does not describe the performance of the resulting system.

Chapter reference: math, worked example & code

This section belongs to the whole chapter, so it is the same on every lesson in it and may cover a different lesson's topic. The code for the experiment you just ran is inside the experiment itself.

Math and notation

A weight-traffic lower-bound estimate is

tstep≳Mread/BW.t_{step}\gtrsim M_{read}/BW.

This assumes the stated bytes really traverse the bottleneck bandwidth. KV transfer adds roughly bytes_to_move/network_bandwidth before protocol and synchronization overhead. Batching and caching can change the bytes per produced token.

Worked example

A fictional 14-GB dense weight scan across a sustained 700-GB/s memory path takes at least 14/700=0.02 seconds, giving a 50-step/s bandwidth ceiling under the one-scan-per-step assumption. Real execution includes other memory traffic and work. A 512-MiB KV transfer over 32 GiB/s has a payload-only lower bound of 1/64 second.

Reference code

The following example uses the Python standard library and does not call a remote service.

from math import isclose
assert isclose(14/700,.02)
assert isclose(1/(14/700),50)
transfer=(512*1024**2)/(32*1024**3)
assert isclose(transfer,1/64)

Python examples are provided for study and local execution; this page does not execute Python.

Common mistakes

Peak device bandwidth is not guaranteed sustained application bandwidth. Exact attention can be computed with different memory layouts. Additional GPUs can add communication bottlenecks.