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Horizontal and vertical growth

Route requests across instances and calculate capacity with headroom, startup time and instance failures.

Horizontal and vertical growth

To carry more load you can give one node more resources (vertical) or add more nodes (horizontal). Horizontal growth only helps the part of the work that can be spread out. If 10% of every request is serialised, for example behind a shared lock or a single database, then 2 instances give a 1.818× speed-up, 10 give 5.263×, and no number of instances can ever exceed 1/0.1 = 10×.

serial fraction (locks, shared storage)0.1instances10
speed-up with 10 instances = 1 / (0.1 + 0.9/10) = 5.263 ceiling: 1 / 0.1 = 10 efficiency 0.53
instances12481632
speed-up11.823.084.716.47.8

A bigger instance adds resources to one node; more instances share the work. But shared storage, locks and serial steps do not shrink when you add replicas, so doubling the replicas does not double capacity.

Change the serial fraction and the number of instances.

Predict first. Does doubling application replicas always double end-to-end capacity?

Chapter context

Load balancing distributes work among eligible backends. Scaling changes available capacity. Both require the application to manage state and dependencies so adding a process actually adds useful throughput.

Chapter reference: math, worked example & code

This section belongs to the whole chapter, so it is the same on every lesson in it and may cover a different lesson's topic. The code for the experiment you just ran is inside the experiment itself.

Math and notation

With demand R, per-instance capacity c and intended usable fraction u, require ncu≥Rncu\ge R. To keep that same target after one failure, require (n−1)cu≥R(n-1)cu\ge R. These are rate constraints, not a complete queueing or availability model.

Worked example

Demand is 900 requests/s. Each instance sustains 400 requests/s, but the target usable fraction is 75%, or 300 requests/s. Three instances meet normal demand. Four are required to maintain the same target capacity after losing one: (4−1)×300=900.

Reference code

The following example uses the Python standard library and does not call a remote service.

from math import ceil
demand,capacity,usable=900,400,.75
normal=ceil(demand/(capacity*usable))
resilient=normal+1
assert normal == 3 and resilient == 4
assert (resilient-1)*capacity*usable == demand

Python examples are provided for study and local execution; this page does not execute Python.

Common mistakes

Horizontal scaling can move the bottleneck to a database. Healthy and ready are not identical. A load balancer does not repair session or transaction state lost with a backend.