LLMsLoading progress…

Greedy selection

Compute temperature and candidate filtering, and distinguish sampling from greedy and beam decoding.

Picking the top token

A language model outputs a probability for every possible next token. Decoding is the rule that turns those probabilities into text. The simplest rule is greedy selection: at every step take the single most probable token. It is deterministic, and when two tokens tie you need a stated rule (for example, the lowest index).

But the best choice at each step does not guarantee the best whole sequence: an early choice can lead into a poor continuation.

A tiny model. Step 1: a 0.6, b 0.4. After a: c 0.5, d 0.5. After b: c 0.9, d 0.1. Every sequence then ends.

complete sequenceprobabilitygreedy?
<s> b c </s>0.36
← best
<s> a c </s>0.3
← greedy
<s> a d </s>0.3
<s> b d </s>0.04
greedy picks the top token at every step: a (0.6), then c (tie with d: the first alphabetically) greedy sequence probability = 0.6 · 0.5 = 0.3 best sequence <s> b c </s> = 0.4 · 0.9 = 0.36

Greedy is deterministic (the same input gives the same output), unlike sampling, but a locally best step need not lead to the best whole sequence. Ties need a stated rule.

A four-sequence model. Greedy's path is not the most probable sequence.

Predict first. Is greedy selection the same as drawing a random token?

Chapter context

Decoding chooses tokens from the model's output distribution. It changes generated behavior without retraining the model. Sampling settings influence diversity and concentration, but they do not independently guarantee correctness or creativity.

Chapter reference: math, worked example & code

This section belongs to the whole chapter, so it is the same on every lesson in it and may cover a different lesson's topic. The code for the experiment you just ran is inside the experiment itself.

Math and notation

pi(T)=exp⁡(zi/T)∑jexp⁡(zj/T),T>0.p_i(T)=\frac{\exp(z_i/T)}{\sum_j\exp(z_j/T)},\quad T>0.

Top-p retains a probability-sorted prefix with cumulative mass at least p, then renormalizes the retained entries. Specify tie handling and any minimum-candidate rule in implementation.

Worked example

For logits [2,1,0] at temperature one, probabilities are approximately [0.665241,0.244728,0.090031]. With top-p=0.8, keep the first two because the first alone is below the threshold. Their renormalized probabilities are approximately [0.731059,0.268941].

Reference code

The following example uses the Python standard library and does not call a remote service.

from math import exp,isclose
weights=[exp(v-2) for v in [2,1,0]]
probs=[w/sum(weights) for w in weights]
assert probs[0] < .8 < sum(probs[:2])
retained=[p/sum(probs[:2]) for p in probs[:2]]
assert isclose(probs[0],.6652409557748218)
assert isclose(retained[0],.7310585786300049)
assert isclose(sum(retained),1)

Python examples are provided for study and local execution; this page does not execute Python.

Common mistakes

Top-p=.8 does not mean keeping 80% of vocabulary items. A high temperature does not create new factual knowledge. Filter-and-renormalize order must be explicit.