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Parallel training

Describe a pretraining loop and reason about data, batch size, precision and a simplified compute budget.

Using many devices

Data parallelism gives each device a copy of the model and a share of the batch; their gradients are averaged ("all-reduce") before the update. With equal shares the result equals the single-device gradient. Tensor parallelism splits individual matrices across devices and pipeline parallelism splits the layers into stages that work on different microbatches, leaving some idle time (the bubble) when the pipeline fills and drains.

Data parallelism: one pass takes 80 s on one device. Each device handles a share, then gradients are averaged across devices (communication).

devices8communication seconds2
compute per device = 80 / 8 = 10 s, plus 2 s communication = 12 s speedup = 6.667× (ideal 8×) efficiency 83.3%

Pipeline parallelism cuts the model into stages. At the start and end some stages sit idle (the bubble):

stages p4microbatches m8
idle fraction = (p − 1) / (m + p − 1) = 3 / 11 = 0.273
8 devices do not give 8×: communication is not divided. Below, the pipeline bubble.

Predict first. Is the ideal arithmetic division by GPU count a complete wall-clock model?

Chapter context

Pretraining optimizes next-token predictions over a dataset. Its costs depend on the architecture, sequence lengths, implementation and hardware. A useful budget model states which work it approximates and which work it ignores.

Chapter reference: math, worked example & code

This section belongs to the whole chapter, so it is the same on every lesson in it and may cover a different lesson's topic. The code for the experiment you just ran is inside the experiment itself.

Math and notation

A commonly used rough dense-transformer training estimate is

C≈6ND,C\approx6ND,

with N model parameters, D training tokens and C floating-point operations. It omits some architecture-dependent work and is not a hardware throughput guarantee. Effective token batch is approximately B×T×AB\times T\times A for microbatch B, length T and A accumulation steps.

Worked example

For N=1 million parameters and D=100 million training tokens, the rough compute estimate is 6×10^6×10^8=6×10^14 FLOPs. A microbatch of 4 sequences of length 8 accumulated twice contributes 64 token positions per optimizer update. Neither calculation includes padding exclusions or communication time.

Reference code

The following example uses the Python standard library and does not call a remote service.

N,D=1_000_000,100_000_000
assert 6*N*D == 600_000_000_000_000
batch,length,accumulation=4,8,2
assert batch*length*accumulation == 64

Python examples are provided for study and local execution; this page does not execute Python.

Common mistakes

Compute-optimal ratios are model- and study-dependent. Train/test leakage can arise from shared documents and overlap. Tokens per update and optimizer steps are different units.