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Internal fragmentation

Allocate logical token blocks to physical KV-cache blocks and quantify internal waste and shared-prefix behavior.

Internal fragmentation: the half-empty last block

A sequence rarely fills its last block exactly. A 33-token sequence in blocks of 16 needs ceil(33/16) = 3 blocks, which is 48 slots; 15 of them are empty. That slack is 15/48 = 31.25% of this allocation, not 31.25% of all GPU memory. On average the slack is about (block size − 1) / 2 slots per sequence.

tokens33block size16
33 tokens → 3 blocks × 16 = 48 slots slack = 15 slots = 31.25% of this allocation (orange) expected slack for random lengths ≈ (b − 1)/2 = 7.5 slots per sequence

Smaller blocks waste less per sequence but need more table entries and more bookkeeping. Paging cannot remove slack for arbitrary lengths; it makes it small and bounded. The percentage is of this allocation, not of all GPU memory.

Blue = tokens, orange = slack. Try a block size of 8 or 64.

Predict first. Can paging eliminate all internal slack for arbitrary sequence lengths?

Chapter context

Contiguous reservation can waste memory when sequence lengths differ or grow unpredictably. Paging separates a sequence's logical block order from the physical blocks storing its cache.

Chapter reference: math, worked example & code

This section belongs to the whole chapter, so it is the same on every lesson in it and may cover a different lesson's topic. The code for the experiment you just ran is inside the experiment itself.

Math and notation

For length T and block capacity P:

nblocks=⌈T/P⌉,slots=P⌈T/P⌉,slack=slots−T.n_{blocks}=\lceil T/P\rceil,\quad slots=P\lceil T/P\rceil,\quad slack=slots-T.

Slack as a fraction of allocated slots is slack/slots. State the denominator when reporting waste percentages.

Worked example

A sequence has 33 tokens and blocks hold 16. It requires ceil(33/16)=3 blocks, allocating 48 token slots. Fifteen slots are unused, so internal slack is 15/48=31.25% of this allocation. It is not 31.25% of all GPU memory, and shared blocks change total ownership accounting.

Reference code

The following example uses the Python standard library and does not call a remote service.

from math import ceil,isclose
tokens,capacity=33,16
blocks=ceil(tokens/capacity)
slots=blocks*capacity
assert blocks == 3 and slots == 48
assert slots-tokens == 15
assert isclose((slots-tokens)/slots,.3125)

Python examples are provided for study and local execution; this page does not execute Python.

Common mistakes

Paging improves allocation flexibility but does not make memory unlimited. Logical block order differs from physical layout. Internal slack and external fragmentation are different kinds of waste.